unknown 5-11-2019

Here’s a randomly generated cipher of unknown type. The plaintext is a random passage from a file of 33 books concatenated together. I think the encoder ignored some numbers that were in the original book passage. My ID tests didn’t do too well: The correct type didn’t appear unless I set the maximum period high enough. With a high maximum period the correct type was in second place in all three ID tests.

It took awhile to stumble upon the correct hill-climbing options but then my PH hill-climber solved it without a crib. I’ll include a caesar-shifted hint and crib.

???.
LHEOH CEXVR WCVGD HLFMS UWWCR SIKAS HFWAM CLVPY NMUFE HMTUR XXHGE
LBGVK YWPUY EBQDS GMRUA NEXYT ZEHRZ FDOZP AHELA UATRZ EPBIE OHYUF
VRWQO NPTEY BTDXN AAMA

crib: UJYWTQJZRUWT
hint: UJWNTIYMNWYJJS

7 thoughts on “unknown 5-11-2019”

  1. I read the hint (though not the crib), and guessed the right system based on that and the fact that my diagnosis had failed to provide useful results. Forcing that hint and limiting the key length to 13 gave a 12-letter keyword that I haven’t figured out, but all legitimate plaintext.

    1. Yes, those are the same key words that my own “key extender” program got. And in fact that’s also the original key. Maybe there aren’t that many choices for the two key words.

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